Write A Program for Liner Searching
Linear search in C to find whether a number is present in an array. If it's present, then at what location it occurs. It is also known as a sequential search.
Linear search program in C
#include<stdio.h>
#include<conio.h>
void main()
{
int array[100], search, c, n;
{
int array[100], search, c, n;
printf("Enter number of elements in array\n");
scanf("%d", &n);
scanf("%d", &n);
printf("Enter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
scanf("%d", &array[c]);
printf("Enter a number to search\n");
scanf("%d", &search);
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search) /* If required element is found */
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n)
printf("%d isn't present in the array.\n", search);
{
if (array[c] == search) /* If required element is found */
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n)
printf("%d isn't present in the array.\n", search);
getch();
}
}
Linear search C program for multiple occurrences
In the code below we will print all locations at which required element is found and also the number of times it occurs in the list.
#include<stdio.h>
int main()
{
int array[100], search, c, n, count = 0;
printf("Enter number of elements in array\n");
scanf("%d", &n);
printf("Enter %d numbers\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter a number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++) {
if (array[c] == search) {
printf("%d is present at location %d.\n", search, c+1);
count++;
}
}
if (count == 0)
printf("%d isn't present in the array.\n", search);
else
printf("%d is present %d times in the array.\n", search, count);
return 0;
}
int main()
{
int array[100], search, c, n, count = 0;
printf("Enter number of elements in array\n");
scanf("%d", &n);
printf("Enter %d numbers\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter a number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++) {
if (array[c] == search) {
printf("%d is present at location %d.\n", search, c+1);
count++;
}
}
if (count == 0)
printf("%d isn't present in the array.\n", search);
else
printf("%d is present %d times in the array.\n", search, count);
return 0;
}
C program for linear search using a function
#include <stdio.h>
long linear_search(long [], long, long);
int main()
{
long array[100], search, c, n, position;
printf("Input number of elements in array\n");
scanf("%ld", &n);
printf("Input %d numbers\n", n);
for (c = 0; c < n; c++)
scanf("%ld", &array[c]);
printf("Input a number to search\n");
scanf("%ld", &search);
position = linear_search(array, n, search);
if (position == -1)
printf("%d isn't present in the array.\n", search);
else
printf("%d is present at location %d.\n", search, position+1);
return 0;
}
long linear_search(long a[], long n, long find) {
long c;
for (c = 0 ;c < n ; c++ ) {
if (a[c] == find)
return c;
}
return -1;
}
long linear_search(long [], long, long);
int main()
{
long array[100], search, c, n, position;
printf("Input number of elements in array\n");
scanf("%ld", &n);
printf("Input %d numbers\n", n);
for (c = 0; c < n; c++)
scanf("%ld", &array[c]);
printf("Input a number to search\n");
scanf("%ld", &search);
position = linear_search(array, n, search);
if (position == -1)
printf("%d isn't present in the array.\n", search);
else
printf("%d is present at location %d.\n", search, position+1);
return 0;
}
long linear_search(long a[], long n, long find) {
long c;
for (c = 0 ;c < n ; c++ ) {
if (a[c] == find)
return c;
}
return -1;
}
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