C program to find HCF and LCM
C program to find HCF and LCM: The code below find the highest common factor and the least common multiple of two integers. HCF is also known as the greatest common divisor (GCD) or the greatest common factor (GCF).
C programming code
#include <stdio.h>
#include <conio.h>
void main() {
int a, b, x, y, t, gcd, lcm;
int a, b, x, y, t, gcd, lcm;
printf("Enter two integers\n");
scanf("%d%d", &x, &y);
scanf("%d%d", &x, &y);
a = x;
b = y;
b = y;
while (b != 0) {
t = b;
b = a % b;
a = t;
}
t = b;
b = a % b;
a = t;
}
gcd = a;
lcm = (x*y)/gcd;
lcm = (x*y)/gcd;
printf("Greatest common divisor of %d and %d = %d\n", x, y, gcd);
printf("Least common multiple of %d and %d = %d\n", x, y, lcm);
printf("Least common multiple of %d and %d = %d\n", x, y, lcm);
getch();
}
}
Output:-
C program to find hcf and lcm using recursion
#include <stdio.h>
#include <conio.h>
long gcd(long, long);
void main() {
long x, y, hcf, lcm;
long x, y, hcf, lcm;
printf("Enter two integers\n");
scanf("%ld%ld", &x, &y);
scanf("%ld%ld", &x, &y);
hcf = gcd(x, y);
lcm = (x*y)/hcf;
lcm = (x*y)/hcf;
printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);
printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
getch();
}
}
long gcd(long a, long b) {
if (b == 0) {
return a;
}
else {
return gcd(b, a % b);
}
}
if (b == 0) {
return a;
}
else {
return gcd(b, a % b);
}
}
C program to find Hcf and Lcm using function
#include <stdio.h>
#include <conio.h>
long gcd(long, long);
void main() {
long x, y, hcf, lcm;
long x, y, hcf, lcm;
printf("Enter two integers\n");
scanf("%ld%ld", &x, &y);
scanf("%ld%ld", &x, &y);
hcf = gcd(x, y);
lcm = (x*y)/hcf;
lcm = (x*y)/hcf;
printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);
printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);
getch();
}
}
long gcd(long x, long y) {
if (x == 0) {
return y;
}
if (x == 0) {
return y;
}
while (y != 0) {
if (x > y) {
x = x - y;
}
else {
y = y - x;
}
}
if (x > y) {
x = x - y;
}
else {
y = y - x;
}
}
return x;
}
}
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